L024 · Allow 10–15 minutes for learners ready to move on. Answers are available after an attempt.
Solve 2x+5=17, then give the third term of 3n+2.
x=6; third term=11.
A learner extends 2,5,8,11 with 15. Diagnose and find the 20th term.
Common difference is 3, next 14; nth term 3n−1 gives term 20=59.
Lesson L024: Cumulative checkpoint and feedback
Objective: Use independent evidence across number, proportion and algebra to identify a specific error and demonstrate a repaired method.
60-minute structure: 0-7 Connect & Check; 7-14 Share; 14-25 Present/model; 25-44 Apply route choice/practice; 44-52 independent exam-style check; 52-60 Recall & Review, WWW/EBI and next step.
I used my working and assessment evidence to identify the exact mathematical step that was secure and the specific misconception that needs attention.
I will correct one precise step, explain why the correction works and complete a fresh delayed question without the original scaffold.
Stretch: Solve 2x+5=17, then give the third term of 3n+2.
Deep challenge: A learner extends 2,5,8,11 with 15. Diagnose and find the 20th term.